A bag contains 10 mangoes out of which 4 are taken out together . if one of them is found to be good, the probability that other is also good is
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The box has 4 rotten mangoes and 6 good mangoes.
Now probability of selecting one good mango from the box is number of good mangoes by total number of mangoes.
that is P1 = 6 / 10.
After selecting one good mango, we have 9 mangoes left. 4 are rotten and 5 are good mangoes.
Now probability of selecting one good mango is 5/9.
Thus P2 = 5/9
Total probability P = P1*P2 = (6/10) * (5/9)
Now probability of selecting one good mango from the box is number of good mangoes by total number of mangoes.
that is P1 = 6 / 10.
After selecting one good mango, we have 9 mangoes left. 4 are rotten and 5 are good mangoes.
Now probability of selecting one good mango is 5/9.
Thus P2 = 5/9
Total probability P = P1*P2 = (6/10) * (5/9)
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