a bag contains 10 marbles of blue color,12 marbles of green color, 17 marbles of black color. if one marble is drawn at random then find the probability that it is?
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first of all add all the marbles then u get
blue colour = 10
green colour = 12
black colour = 17
add all the above for getting total no. of marbles
10+12+17 =39
so total number of marbles is 39
P(E) = possible outcome / total outcome
so according to this
1) blue marbles, 10/39
2)green marble,12/39
3)black marble,17/39
blue colour = 10
green colour = 12
black colour = 17
add all the above for getting total no. of marbles
10+12+17 =39
so total number of marbles is 39
P(E) = possible outcome / total outcome
so according to this
1) blue marbles, 10/39
2)green marble,12/39
3)black marble,17/39
aalimakhan1262001:
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Answered by
0
first of all add all the marbles then u get
blue colour = 10
green colour = 12
black colour = 17
add all the above for getting total no. of marbles
10+12+17 =39
so total number of marbles is 39
P(E) = possible outcome / total outcome
so according to this
1) blue marbles, 10/39
2)green marble,12/39
3)black marble,17/39
blue colour = 10
green colour = 12
black colour = 17
add all the above for getting total no. of marbles
10+12+17 =39
so total number of marbles is 39
P(E) = possible outcome / total outcome
so according to this
1) blue marbles, 10/39
2)green marble,12/39
3)black marble,17/39
why u coping my answer
r u crazy to cpy others answer.....?
plzzz try it to your own answer.........
and dont cpy my answers.........
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