A bag contains 10 oranges and 20 apples out of which 5 apples and 3 oranges are defective .If a person takes out two at random, what is the probability that either both are good or both are apples ?
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Step-by-step explanation:
Let probability of selecting two oranges be P(A) ,
P(A) = 20/30 x 19/30 = 19/45
Let probability of selecting two two non-defective item be P(B),
P(B) = 22/30 x 21/30 = 77/150.
P( A OR B) = P(A) + P (B)
= 19/45 + 77/150 = 421/450 = 0.0.93555556.
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