Question

a bag contains 10 red balls and 8 white balls,find the probability of picking one white ball.​

Answer 1

Answer:-

$total \: number \: of \: balls = 18 \\ total \: number \: of \: white \: balls = 8 \\ total \: number \: of \:red \: balls = 10 \\ probability = \binom{possible \: outcome}{total \: no \: of \: outcomes } \\ 8 \div 10 = 4by5$

Answer 2

Answer:

Hence, the required probability of getting a white ball , P(E) = 4/9

Step-by-step explanation:

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