A bag contains 10 rupees, 2 rupees and 1 rupee coins. The value of 10 rupees, 2 rupees and 1 rupeecoins are in the ratio of 15 : 8 : 1 respectively. If total number of coins is 273, then what will be the total value(in Rs) of all coins?
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Answer:answer is 12
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The total value of all the coins in the bag is Rs. 1008.
- The ratio of values of 10 rupees , 2 rupees and 1 rupee coins in the bag is 15 : 8 : 1.
- Let the common multiple be x.
- Now ,
The value of 10 rupees coins in the bag will be 15x.
The value of 2 rupees coins in the bag will be 8x.
The value of 1 rupee coins in the bag will be x.
- Now,
The number of coins of rupees 10 = 15x / 10 = 1.5x
The number of coins of rupees 2 = 8x / 2 = 4x
The number of coins of rupee 1 = x / 1 = x
- Total number of coins = 273
1.5x + 4x + x = 273
6.5x = 273
x = 42.
- Therefore the value of x is 42.
- Now,
The value of 10 rupees coins in the bag is 15x = 15 × 42 = 630
The value of 2 rupees coins in the bag is 8x = 8 × 42 = 336
The value of 1 rupee coins in the bag is x = 42.
- The total value of all the coins in the bag = 630 + 336 + 42 = Rs. 1008
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