A bag contains 10 white balls , 5 black balls, 3 green balls and 2 red balls . One
ball is drawn at random. Find the probability that the ball drawn is white or black.
Answers
Answered by
0
Let W,B,G be the event of selecting a white, black, green ball respectively.
n(S)=10+5+3+2=20
n(W)=10,n(B)=5,n(G)=3
P(W)=
n(S)
n(W)
=
20
10
P(B)=
n(S)
n(B)
=
20
5
P(G)=
n(S)
n(G)
=
20
3
Probabilities of getting white or black or green ball
=P(W∪B∪G)
(W,B,G are mutually exclusive event)
=P(W)+P(B)+P(G)
=
20
10
+
20
5
+
20
3
=
20
18
=
10
9
Answered by
1
Answer:
3/4
Step-by-step explanation:
Total no. of balls= 20
No. of white balls = 10
No. of black ball= 5
Probability = Total no. of white and black ball/ total balls
=15/20
=3/4
Please mark as brainliest..
Similar questions