Question

A bag contains ₹ 102 in the form of rupee 50 paisa and 10 paisa coins in the ratio 3 : 4 : 10 . The number of 10 paisa coins is.
With correct solution. ​

Answer 1

Answer:

1 (3x) +50/100 (4x )+ 10/100 (10x) =102 =3x+1/2 (4x)+1/10 (10x)=102 3x+2x+x=102 6x=102 x =102/6=17 10x=17×10=170. Number of 10 paise coin is 170. That set.

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Answer 2

Answer:

The number of 10 paisa coins is 170

(₹ 17)

Step-by-step explanation:

Let,

1 Rupee coins = 3x

50 paisa coins = 4x

10 paisa coins = 10x

Total amount in bag = ₹ 102

1 rupee = 100 paisa

So,

₹ 102 × 100

10,200 paisa

⇒ 3x × 100 = 300x

⇒ 4x × 50 = 200x

⇒ 10x × 10 = 100x

★ According to the question :

⇒ 300x + 200x + 100x = 10,200

⇒ 600x = 10,200

⇒ x = 10,200 / 600

⇒ x = 17

____________________________

★ Value of 3x :

⇒ 3 (17)

⇒ 51

1 Rupee coins = 51 coins

____________________________

★ Value of 4x :

⇒ 4 (17)

⇒ 68

50 paisa coins = 68 coins

____________________________

★ Value of 10x :

⇒ 10 (17)

⇒ 170

10 paisa coins = 170 coins

Therefore,

The number of 10 paisa coins is 170

(₹ 17)