Question

A bag contains 10red balls 15 green balls 5 purple balls of two balls are chosen at random what is the probability that neither of the balls is red

Answer 1

No of red balls = 10

No of green balls = 15

No of people called = 5

Total no of balls = 30

P(ball not being red) = no of green balls + no of purple balls/ total no of balls.

= 15+5/30

= 20/30

= 2/3

= O.666667

Answer 2

$\sf \pmb{Answer :}$

No of red balls = 10

No of green balls = 15

No of people called = 5

Total no of balls = 30

P(ball not being red) = no of green balls + no of purple balls/ total no of balls.

= 15+5/30

= 20/30

= 2/3

= O.666667