A bag contains 1100 tickets numbered 1, 2, 3, … 1100. If a ticket is drawn out of it at random, what is the probability that the ticket drawn has the digit 2 appearing on it?
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Answer:
9/110
Step-by-step explanation:
Total no.of tickets n(s) =1100
No.of two digited tickets n(E)= 90
P(E)= n(e)/n(s)
P(E)= 90/1100
"0" will be cancelled in numerator and. denominator
so answer = 9/110
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