Question

a bag contains 12 balls of which 3 are red balls.5 balls are drawn at random. find the probability that in 5 3 are red balls

Answer 1

Answer:

total outcomes = 12C5 favorable outcomes = 9C2

the P(E) = 9C2/12C5

Answer 2

Answer:

1/22

Step-by-step explanation:

We have 12 balls in which 3 balls are red and 12–3=9 balls of other colour

5 balls can be drawn from 12 in 12C5 ways.

So the sample space is 12C5.

In the favourable case for the event we have all 3 red balls and 2 balls of other colour. The 3 red balls can be selected in 1 way and remaining 2 can be selected from the other colour in 9C2 ways.

So the required probability 9c2/12c5

Upon solving, you get:

(9×8/2) / (12×11×10×9×8/5)

=36/792

= 1/22