A bag contains 12 balls of which x are red, 2x are white and 3x are blue, where x is a positive integer. A ball is selected randomly. The probability of its being not white is :
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answer 4/12,:1/3hhxjiisjijjdijhdjkkrj
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The question clearly says that sum of red balls + white balls + blue balls = 12
So, x + 2x + 3x = 12
6x = 12
X = 2balls
So, number of red balls is = x = 2 balls
Number of white balls is =2x = 2×2 = 4 balls
Number of blue balls is = 3x = 3×2 = 6 balls
PROBABILITY OF NOT GETTING WHITE BALL IS :
TOTAL NUMBER OF OUTCOMES = 12
NUMBER OF FAVORABLE OUTCOMES = 12 - 4 = 8
HENCE, THE PROBABILITY IS 8/12 = 4/5
HOPE IT WILL HELP YOU A LOT... BRO..
So, x + 2x + 3x = 12
6x = 12
X = 2balls
So, number of red balls is = x = 2 balls
Number of white balls is =2x = 2×2 = 4 balls
Number of blue balls is = 3x = 3×2 = 6 balls
PROBABILITY OF NOT GETTING WHITE BALL IS :
TOTAL NUMBER OF OUTCOMES = 12
NUMBER OF FAVORABLE OUTCOMES = 12 - 4 = 8
HENCE, THE PROBABILITY IS 8/12 = 4/5
HOPE IT WILL HELP YOU A LOT... BRO..
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