A bag contains 12 balls out of which p are green,
(i) If one ball is drawn at random find the probability that it is green.
(ii) If 6 more green balls are put in the bag, the probability of drawing a green ball will be double than that in part (i). Find p.
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Answer:
total no. Possible outcome=12
total no. of outcome=p
so, probablity of getting green ball=p/12
again, (p+6) /18=2×p/12
so, p=3
total no of green ball=3
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