A bag contains 12 balls out of which x are black
1. If a ball is drawn at random, what is the probability that it will be black? 2. If 6 more black balls are put in the bag the probability of drawing a black ball will be doubled that of above. Find value of x
Answers
Question:-
A bag contains 12 balls out of which x are black
- If a ball is drawn at random, what is the probability that it will be black?
- If 6 more black balls are put in the bag the probability of drawing a black ball will be doubled that of above. Find value of x
Answer:-
Answer 1
P(getting black ball) = ( Number of favourable events ) / (Total number of possible events)
Given: Total number of possible outcomes = Total number of balls = 12
Total number of favourable events = Number of black balls = x
Therefore, P(getting black ball) = x/12
Answer = x/12
Answer 2
Given: 6 more black balls are put in the bag
New probability = 2(original probability) = 2(x/12)
New, total number of favourable events = x + 6
new Total number of possible outcomes = 12 + 6
p(getting black ball) = (Number of favourable events)/(Total number of possible events)
=> 2(x/12) = (x + 6) / (12 + 6)
=> x/6 = (x + 6) / 18
=> 18 * x/6 = x + 6
=> 3x = x + 6
=> 2x = 6
=>x=6/2
=> x = 3
Answer = 3
Answer:
Question:-
A bag contains 12 balls out of which x are black
If a ball is drawn at random, what is the probability that it will be black?
If 6 more black balls are put in the bag the probability of drawing a black ball will be doubled that of above. Find value of x
Answer:-
Answer 1
P(getting black ball) = ( Number of favourable events ) / (Total number of possible events)
Given: Total number of possible outcomes = Total number of balls = 12
Total number of favourable events = Number of black balls = x
Therefore, P(getting black ball) = x/12
Answer = x/12
Answer 2
Given: 6 more black balls are put in the bag
New probability = 2(original probability) = 2(x/12)
New, total number of favourable events = x + 6
new Total number of possible outcomes = 12 + 6
p(getting black ball) = (Number of favourable events)/(Total number of possible events)
=> 2(x/12) = (x + 6) / (12 + 6)
=> x/6 = (x + 6) / 18
=> 18 * x/6 = x + 6
=> 3x = x + 6
=> 2x = 6
=>x=6/2
=> x = 3
Answer = 3
Step-by-step explanation: