Question

a bag contains 12 balls out of which x balls are white. if one ball is taken out from the bag, find the probability of getting white ball. if 6 more white balls are added to the bag and now the probability of getting a white ball is double the previous one, find the value of x. ​

Answer 1

heya mate...☺

here's ur answer...✌✌

No of balls = 12

No of white balls = x

Required probability of getting white balls = $\frac{x}{12}$

Now,

No of balls added = 6

Total balls = 18

Probability of getting white balls = $\frac{x+6}{18}$

Equation formed:

=> $\frac{x+6}{18} = {2x}/{12}$

=> 12x + 72 = 36x

=> 24x = 72

=> x = 3

Therefore,

Value of x = 3

hope it helps ...

Answer 2

Answer:

Step-by-step explanation:

Case one

Probability =x/12

Case two

Probability=x+6/12=2*x/12

=x+6/12=x/6

=x+6=12*x/6

=x+6=2x

=x=6