A bag contains 12 black cards, 14 red cards and 12 green cards. What is the probability of drawing a black card first and then a red card with replacement?
Answers
1.) Total cards= 38 ; Black card = 12
(The probability of selecting black card)
P(black)= 12/38 = 6/19
2.) Red card= 14
Since the card is replaced total number of card will remain same so, probability of selecting red card is
P(red)= 14/38 = 7/19
Therefore, probability of selecting black card first and then a red card with replacement is calculated as:
= 6/19 * 7/19= 42/361
1. Total number of cards = 12+14+12=38
The probability of selecting black cards is
P(black) = \frac{12}{38} = \frac{6}{19}P(black)=
38
12
=
19
6
Since the cards is replaced, so total number of cards will remain same.
So, the probability of selecting red cards is
P(red) = \frac{14}{38} = \frac{7}{19}P(red)=
38
14
=
19
7
Therefore, the probability of selecting a black cards first and then a red cards with replacement is calculated as follows:
P(black, \; then \; red) = P(black) \times P(red) \\ = \frac{6}{19} \times \frac{7}{19} \\ = \frac{42}{361}P(black,thenred)=P(black)×P(red)
=
19
6
×
19
7
=
361
42