A bag contains 12 blue balls and x red balls. If one ball is drawn at random (i) what is
the probability that it will be a red ball? (ii) If 8 more red balls are put in the bag, and if
the probability of drawing a red ball will be twice that of the probability in (i), then find x.
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x is equal to 4
(i) probability of red balls thus become 4/16
which is equal to 1/4
(ii) probability of red balls= 4+8/12+4+8
I.e 12/24= 1/2
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