A bag contains 12 two rupee coins ,7 one rupee coins and 4 half rupee coins .if three coins are selected at random then find the probabbility that the sum of three coins is maximum
Answers
Answer:
plz mark brainlest answer plz mark brainlest answer plz
Step-by-step explanation:
The bag contains 12 two rupee coins, 7 one rupee coins and 4 half a rupee coins.
Total coins in the bag =12+7+4=23
Selecting three coins from the bag =
23
C
3
=1771
Sum of three coins will be maximum when all the three coins selected are of rupee two.
Therefore,
Selecting three coins of rupee two =
12
C
3
=220
Probability of selecting three coins with maximum sum =
1771
220
=
161
20
Sum of three coins will be minimum when all the three coins selected are of half a rupee coin.
Therefore,
Selecting three coins of half a rupee =
4
C
3
=4
Probability of selecting three coins with minimum sum =
1771
4
Selecting three different coins =12
1
C
×
7
C
1
×
4
C
1
=12×7×4=336
Probability of selecting three different coins from the bag =
1771
336
=
253
48