Question

) A bag contains 12 white, 8 black and 6 red balls. One ball is picked randomly, find the probability that ball picked is black or red​

Answer 1

Step-by-step explanation:

Total no. of balls in the bag is 18 (8 red, 4 black and 6 white)

Solution(i):

No. of red or white balls in bag is 14 (8 red and 6 white)

Therefore,

14

C

1

( Selecting 1 out of 14 items) times out of

18

C

1

( Selecting 1 out of 18 items) a red or white ball is picked.

Let E be the event of drawing a red or white ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

18

C

1

14

C

1

=

18

14

=

9

7

Solution(ii):

No. of non-black balls in bag is 14 (8 red and 6 white)

Therefore,

14

C

1

( Selecting 1 out of 14 items) times out of

18

C

1

( Selecting 1 out of 18 items) a non-black ball is picked.

Let E be the event of drawing a non-black ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

18

C

1

14

C

1

=

18

14

=

9

7

Solution(iii):

No. of neither black nor white balls in bag is 8 (8 red balls)

Therefore,

8

C

1

( Selecting 1 out of 8 items) times out of

18

C

1

( Selecting 1 out of 18 items) a neither white nor black ball is picked.

Let E be the event of drawing a neither white nor black ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

18

C

1

8

C

1

=

18

8

=

9

4

Answer 2

Step-by-step explanation:

Total number of outcomes=26

Number of black balls= 8

Probability of getting a black ball=

$\frac{8}{26} = \frac{4}{13}$

Number of red balls=6

Probability of getting a red ball

$\frac{6}{26} = \frac{3}{13}$