Question

A bag contains 12 white and 18 black balls. Two balls are drawn in succession without replacement. What is the probability that first is white and second is black?

Answer 1

Hi .....here is your solution..

Answer 2

Answer:

36/145

Step-by-step explanation:

Since , a bag contains 12 white and 18 black balls.

Since , two balls are drawn in succession without replacement.

Total balls = 12 white + 18 balls  =  30

Probability of drawing white balls first = number of white ball/total balls

                                                                = 12/30

Now, the 1 ball have been reduced from the total balls;

Now, the total balls left = 29

Probability of drawing black ball for the second time = 18/29

Now, the combined probability of drawing first is white and second is black would be $\frac{12}{30} \times \frac{18}{29}$

= 36/145

the probability that first is white and second is black = 36/145