Question

a bag contains 12 whole 1 by 2 kg of flour .two fifth of the floor was added to the same bag .how much of the weight is added?​

Answer 1

Answer:

12 whole 9/10 kg

Step-by-step explanation:

=12whole 1/2 +2/5

=25/2+2/5

=125+4/10

=129/10

=12whole 9/10

Answer 2

Given :

what it already has -

$12 \times \frac{1}{2}$

To find :

when of the flour is added

$\frac{2}{5}$

STEP BY STEP GUIDE

$\frac{2}{5} + 12 \times \frac{1}{2}$

$\frac{2}{5} + \frac{25}{2}$

$\frac{104}{10}$

$\frac{52}{5}$

The total amount is

$10 \times \frac{2}{5}$