a bag contains 13 blue balls 6 black ball find the probability a red ball and black ball
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Answer:
Use law of totalprobability
P(r) = p(r|bag a) p( bag a) + p r|bag b) p(bag b)
P( bag a) = p(bag b)= 1/2
If from bag a( 3r, 8b) p(r| a)= 3/(3+8)=3/11
If from bag b(5r, 7b), p( r|b) = 5/(5+7)= 5/12
Putting it together
1/2*(3/11+5/12)
Step-by-step explanation:
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