Question

A bag contains 135 Rs in the form of 1 ruppee, 50 paisa, 25 paisa in the ratio 3:5:8. Find the number of coins of each type​

Answer 1

Step-by-step explanation:

3:5:8 is the ratio of coins of 1 Rupee, 50 paisa and 25 paisa.

Ratio in the number of coins of each type

3 : 5×2 : 8×4

= 3 : 10 : 32

Sum of the ratios = 3 + 10 + 32 = 45

No. of Coins of 1 Rs. = (135 × 3)/45 = 9

No. of Coins of 50 P. = (135 × 10)/45 = 30

No. of Coins of 1 Rs. = (135 × 32)/45 = 96

Hope it helps.

Answer 2

Step-by-step explanation:

a bag contains =135rs

in the form of =1rupee,50paisa,

25paisa

in the ratio of =3:5:8

no. of. coins =?

=1×3+50p×5+25p×8=135

3rupees+250paise+200paise

1rupee=100paise

then,

450paise=4.50rupees

so, 3×4.50=13.5×100=135

then the coins are 3,70,60

thank you