Question

A bag contains 15 balls of three different colour green,black,and yellow A ball is drawn at random from the bag the probability of green ball is 1/3.. the probability of of yellow ball is 1/5 (a) what is the probability of black ball? (b) how many balls are green?

Answer 1

answer of 1 is 7/15


answer of b is 5

Answer 2

Answer:

(a) probability of black ball = $\dfrac{7}{15}$

(b) number of green balls = 5

Step-by-step explanation:

Total number of ball = 15

probability of green ball = $\dfrac{1}{3}$

hence, the number of green ball = total number of ball x probability of green ball

                                                        $= 15\times \dfrac{1}{3}$

                                                         = 5

probability of yellow ball = $\dfrac{1}{5}$

so, the number of yellow ball = total number of ball x probability of yellow ball

                                                 $= 15\times \dfrac{1}{5}$

                                                   = 3

So, the number of black ball = total number of ball - number of green ball - number of yellow ball

                                                = 15 - 5 - 3

                                                 = 7

Hence, the probability of getting black ball =$\dfrac{number\ of\ black\ ball}{total\ number\ of\ ball}$

                                                                   $=\dfrac{7}{15}$

Hence, the probability black ball is $\dfrac{7}{15}$ and total number of green ball is 5.