Question

A bag contains 15 balls of which 6 are identical find the number of ways of selecting 8 balls

Answer 1

THEIR ARE MANY WAYS OF GETTING 8 BALLS.

SUCH AS :--

6 IDENTICAL AND 2 NON IDENTICAL

6 NON IDENTICAL AND 2 IDENTICAL

1 IDENTICAL AND 7 NON IDENTICAL

AND SO ON...

Answer 2

Answer:

The possible number of ways are 501.

Step-by-step explanation:

As per the data given in the question,

We have,

Total balls = 15

Identical balls = 6

Different balls = 9

So, ways for selecting 8 balls = ( 8different) + (7 different 1 alike) +....+ (2 different 6 alike)

$=\binom98C+\binom97C+\binom96C+\binom95C+\binom94C+\binom93C+\binom92C\\Using\:binomial\:formula\\=2^{9} -[\binom90C+\binom91C+\binom99C]\\=2^{9} -[1+9+1]\\=512-11\\=501$

Hence, The possible number of ways are 501.

#SPJ3