a bag contains 15 balls of which x are blue and the remaining are red .if the number of red balls are incrrased by 5 the probability of drawing the red ball gets doubles. find p (red balls),p (blue balls).p (blue balls if 5 extraa red balls are actually added
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Total balls=15
Blue balls=x
Red balls=15-x
P(blue balls)=x/15
P(red balls)=15-x/15
If 5 red balls are added then total balls = 15+5=20
Blue balls=x+5
Red balls=15-x+5=20-x
P(red balls)=20-x/20
ATQ, x-5/15=2(20-x/20)
10x-50=300-15x
On solving,x=14
P(red balls)=1/15
P(blue balls)=14/15
P(blue balls if 5 red balls are added)=19/20
Blue balls=x
Red balls=15-x
P(blue balls)=x/15
P(red balls)=15-x/15
If 5 red balls are added then total balls = 15+5=20
Blue balls=x+5
Red balls=15-x+5=20-x
P(red balls)=20-x/20
ATQ, x-5/15=2(20-x/20)
10x-50=300-15x
On solving,x=14
P(red balls)=1/15
P(blue balls)=14/15
P(blue balls if 5 red balls are added)=19/20
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