Question

a bag contains 15 balls some of them are blue red and white the number of white balls is 11 times the number of Blue Balls the number of red balls is less than the numbers of white balls also the number of red balls is more than number of Blue Balls if one of the ball is selected at random from the bag what is the probability that it is a red balls

Answer 1

B + R + W = 15

W = 11 B

B + R + 11 B = 15

12 B + R = 15

R = 15 - 12 B

If B= 1 , R = 3

IF B= 2,3... R becomes negative

SO B= 1

R= 3

W= 11B = 11

R<W

B<R

W>R>B

SO

P( it is red ball) = 3/ ( 1+3 +11) = 3/ 15 = 1/5