A bag contains 15 defective bulbs and 35 non defective bulb .3 bulbs are taken out what is the probability that all the three bulbs are defective
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the probability of the three bulbs are defective is= no. of bulbs taken out/total no. of defective bulbs.
therefore, the probability is 3/15=1/5
therefore, the probability is 3/15=1/5
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