Question

a bag contains 15 marbles - 7 blue - 5 green - 3 red What is the probability that the first marble drawn is blue and the second marble is green? Show working and simplify answer.

Answer 1

______________$\red{♡}\blue{♡}\pink{♡}\purple{♡}\orange{♡}\green{♡}\red{♡♡}$______________

✧ANSWER:-

❥GIVEN:-

TOTAL NO. OF MARBLES IN THE BAG = 15

NO. OF BLUE MARBLES = 7

NO. OF GREEN MARBLES = 5

NO. OF RED MARBLES = 3

❥FIND:-

PROBABILITY OF GETTING F1ST MARBLE AS BLUE=?

AND 2ND MARBLE AS RED=?

❥SOLUTION:-

1)

TOTAL NO. OF MARBLES= 15

NO. OF BLUE MARBLES = 7

so,

$probability (e_{1} ) = \frac{favourable \: outcmes}{total \: outcomes}$

$= \frac{ \cancel7}{ \cancel15} = 0.46$

so, the probability of getting f1st marble as blue is 0.46

2)

TOTAL NO. OF MARBLES= 15

NO. OF GREEN MARBLES =5

so,

$probability (e_{2} ) = \frac{favourable \: outcmes}{total \: outcomes}$

$= \frac{ \cancel5}{ \cancel15} = 0.33$

so, the probability of getting 2nd marble as green is 0.33

$\red{♡}\blue{♡}\pink{♡}\purple{♡}\orange{♡}\green{♡}\red{♡♡}{♡}\blue{♡}\pink{♡}\purple{♡}\orange{♡}\green{♡}\red{♡♡}\red{♡}\blue{♡}$