A bag contains 15 red balls and 20 black balls. Each ball is numbered either 1 or 2 or 3. 20% of the red balls are numbered 1 aild 40% of them are numbered 3. Similarly, among the black balls, 45% arc numbered 2 and 30% are numbered 3. A boy picks a ball at random. He wins if the ball is red and numbered 3 or if it is black and numbered 1 or 2. What are the chances of his winning?
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mark as branliest and I hope it helps
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baba15791:
explain it little bit...
15+20=35 and then 15/35 and 20/35=3/7and 4/7 respectively then I suppose it is easy
thanks bro.....but in black 1 and 2 ie ans 4/7
it is written check
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Answer:
total balls in the bag are 15+20=35
red balls with no. 3 = 15×40/100=6
black balls with no.2 = 20×45/100=9
similar balls with no.1 =20-9-20×30/100=5
total no.of black balls with no.1 or no.2 =9+5=14
@hence winning probity=6+14/35= 20/35=4/7
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