A bag contains 15 white and some black balls.If the probability of drawing a black ball from the bag is thrice that of drawing a white ball find the number of black balls in the bag
Answers
Answered by
1
No. of white balls=15
let the no. of black balls = x
probability of drawing a white ball = 15/(15+x)
probability of drawing a black ball = x/(15+x)
According to given condition-
x/(15+x)=3*15/(15+x)
x=3*15
=45
therefore the no. of black balls = 45
let the no. of black balls = x
probability of drawing a white ball = 15/(15+x)
probability of drawing a black ball = x/(15+x)
According to given condition-
x/(15+x)=3*15/(15+x)
x=3*15
=45
therefore the no. of black balls = 45
Answered by
0
Number of white balls = 15
Let total number of balls be x.
So, Number of black balls = x - 15.
Probability of drawing a white ball, P ( W) = 15 /x
Probability of drawing a black Ball, P( B)
= (x - 15 ) /x
ATQ,
P( B) = 3 P ( W )
( x - 15) /x = 3 × 15 / x
x - 15 = 45
x = 45 +15 = 60.
Number of black balls = ( x - 15 ) = 60 - 15 = 45
Let total number of balls be x.
So, Number of black balls = x - 15.
Probability of drawing a white ball, P ( W) = 15 /x
Probability of drawing a black Ball, P( B)
= (x - 15 ) /x
ATQ,
P( B) = 3 P ( W )
( x - 15) /x = 3 × 15 / x
x - 15 = 45
x = 45 +15 = 60.
Number of black balls = ( x - 15 ) = 60 - 15 = 45
Similar questions