A bag contains 18 balls out of which x balls are red.
(1)If one ball is drawn at random from the bag,what is the probablity that it is not red?
(2)If 2 more red balls are put in the bag,the probablity of drawing a
red ball will be 9/8 times the probablity of drawing a red ball in the first case.Find the value of x.
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Total number of balls = 18
Number of red balls = x
(1) p(red ball)=x/18
(2) 2 more red balls are put in the bag.
Now,the total number of balls 18+2=20
Now,p(red ball)=x+2/20
According to question
x+2/20=9/8×x/8
x+2/20=x/18
x+2/20=x/16
16x+32=20x
4x=32
x=8
hope it helps you
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