Question

A bag contains 18 balls out of which x balls are red
a) If one ball is drawn of random from the bag, what is the probability that it is not a red ?
b) If two more red balls are put in the bag, the probability of drawing a red ball will be
9/8 times the probability of drawing a red ball in the first case, find the value of x.


Answer the question plz..

Answer 1

Step-by-step explanation:

(a)balls in bag=18

red ball=x

not red=18-x

probability of not red=(18-x)/18

(b)

red=x+2

total=20

probably of drawing red=(x+2) /20

hence,

(x+2)/20=9x/144

144x+288=180x

36x=288

x=8

hope this help

Answer 2

$\fbox\pink{A}\fbox\blue{n}\fbox\purple{s}\fbox\green{w}\fbox\red{e}\fbox\orange{r}$

Step-by-step explanation:

(a)balls in bag=18

red ball=x

not red=18-x

probability of not red=(18-x)/18

(b)

red=x+2

total=20

probably of drawing red=(x+2) /20

hence,

(x+2)/20=9x/144

144x+288=180x

36x=288

x=8