Math, asked by sumitchoudhary70995, 4 months ago

A bag contains 18 balls out of which x balls are red.

(i) If one ball is drawn at random from the bag , what is the probability that it

is not red?

(ii) If two more red balls are added in the bag, the probability of drawing a

red ball will be 9

8

times the probability of drawing a red ball in the first

case. Find the value of x.​

Answers

Answered by Mokxya
1

Answer:8

Step-by-step explanation:

bag contains =18 balls

no. of red balls =x

Probability of red ball =  

total no of ball

Favourable ball

​  

 

(i) P[red ball]=  

18

x

​  

 

(ii) If two more red ball add  

no. of red ball =x+2

total no. of balls =18+2=20

Probability of druuing red ball =  

8

9

​  

 Probability of red ball coming in part (i)

∴  

20

x+2

​  

=  

8

9

​  

×  

18

x

​  

 

∴   20 x+2 =16 x

​  

 

∴ 16(x+2)=20 x

∴ 16 x+32=20 x

∴ 20 x−16 x=32

∴ 4 x=32

∴ x=8

→ the value of x=8

Answered by poornimasankar
2

Answer:

bag contains =18 balls

no. of red balls =x

Probability of red ball =

total no of ball

Favourable ball

(i) P[red ball]=

18

x

(ii) If two more red ball add

no. of red ball =x+2

total no. of balls =18+2=20

Probability of druuing red ball =

8

9

Probability of red ball coming in part (i)

20

x+2

=

8

9

×

18

x

20

x+2

=

16

x

∴ 16(x+2)=20 x

∴ 16 x+32=20 x

∴ 20 x−16 x=32

∴ 4 x=32

∴ x=8

→ the value of x=8

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