A bag contains 18 balls out of which x balls are red.
(i) If one ball is drawn at random from the bag , what is the probability that it
is not red?
(ii) If two more red balls are added in the bag, the probability of drawing a
red ball will be 9
8
times the probability of drawing a red ball in the first
case. Find the value of x.
Answers
Answer:8
Step-by-step explanation:
bag contains =18 balls
no. of red balls =x
Probability of red ball =
total no of ball
Favourable ball
(i) P[red ball]=
18
x
(ii) If two more red ball add
no. of red ball =x+2
total no. of balls =18+2=20
Probability of druuing red ball =
8
9
Probability of red ball coming in part (i)
∴
20
x+2
=
8
9
×
18
x
∴ 20 x+2 =16 x
∴ 16(x+2)=20 x
∴ 16 x+32=20 x
∴ 20 x−16 x=32
∴ 4 x=32
∴ x=8
→ the value of x=8
Answer:
bag contains =18 balls
no. of red balls =x
Probability of red ball =
total no of ball
Favourable ball
(i) P[red ball]=
18
x
(ii) If two more red ball add
no. of red ball =x+2
total no. of balls =18+2=20
Probability of druuing red ball =
8
9
Probability of red ball coming in part (i)
∴
20
x+2
=
8
9
×
18
x
∴
20
x+2
=
16
x
∴ 16(x+2)=20 x
∴ 16 x+32=20 x
∴ 20 x−16 x=32
∴ 4 x=32
∴ x=8
→ the value of x=8