Question

A bag contains 18 balls out of which x balls are red.
If one ball is drawn at random from the bag, what is the probability
that it is not red?
(ii) If two more red balls are put in the bag, the probability of drawing
a red ball will be times the probability of drawing a red ball in the
first case. Find the value of x.​

Answer 1

Answer:

Step-by-step explanation:

Total No . of Obs = 18

No . of Red Balls = x

Probability of Red Ball = Favourable Obs / Total No. of Obs

P(of Red Ball) = x/18

Two Red Balls Are Added

So,

No . of Red Balls = x + 2

Total no .of Balls = 18 + 2 = 20

P(of red Ball) = x + 2 / 20

P given 9 times of P obtained in A

9/8 * x/18 = (x + 2)/20

x / 16 = (x + 2)/20

(x / 16) *  20 = x + 2

5x / 4 = x + 2

5x = 4x + 8

5x - 4x = 8

x = 8

Therefore,

Initial No.Of Red Balls = 8

Answer 2

i) P(E) =18-x/18

ii) yr second question is incomplete please give the number by which the probability increased