Question

a bag contains 18 balls out of which x balls are red if two more red balls are put in bag the probability of drawing a red ball will be 9/8 times the probability of drawing a red ball in first case. find value of x ​

Answer 1

Answer:

8

Step-by-step explanation:

Probability of each ball is 1/18

If there were x red balls, the probabilty was x/18

Now 2 balls added and probabilty changed to (x+2)/20

(x+2)/20=x/18*9/8

(x+2)/20=x/16

20x=16x+32

4x=32

x=8 red balls

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Answer 2

Answer:

Given,

Total balls = 18

Red balls = x

Two more red balls are added so,

Red balls = x + 2

Probability of getting red balls = 9 / 8

Linear equation :-

$\frac{x + 2}{18} = \frac{9}{8} \\ lcm = 72 \\ \frac{4(x + 2)}{72} = \frac{9 \times 9}{72} \\ \frac{4x + 8}{72} = \frac{81}{72} \\ cancel \: base \: on \: both \: sides \\ 4x + 2 = 81 \\ 4x = 81 - 2 \\ 4x = 79 \\ x = \frac{79}{4}$