Question

A bag contains 18 balls out of which xballs are red,
one ball is drawn at random from the bag, what is the probability that it is not red
(2)
2 more red balls are put in the bag, the probability of drawing a red ball will be
9/8 times the
probability of drawing a red ball in the first case. Find the value of x.​

Answer 1

Answer:

1-(x/18);

Step-by-step explanation:

1) P(red balls)=x/18

P(not a red ball)=1-(x/18)

2) new total no. of balls in bag = 18+2=20

new no. of red balls = x+2

new. P(red balls) = (x+2)/20

but A/q,

new. P(red balls)= (9/8) * old P(red balls)

so. (x+2)/20 = (9/8)*(x/18)

after solving the equation

x=8