A bag contains 187 Rs in the form of 1 Rupees 50 paisa & 10 paisa coins in 8:4:5 find no.of coins of each type
Answers
Answered by
8
Total money= 187
coins in 1 re
= 8x
coins in 50 Paisa
= 4x
coins in 10 Paisa
= 5x
8x+4x+5x= 187
17x= 187
x= 11
8x=8*11=88{number of re 1 coins}
4x=4*11=44{number of 50 Paisa coins}
5x=5*11=55{number of 10 Paisa coins}
coins in 1 re
= 8x
coins in 50 Paisa
= 4x
coins in 10 Paisa
= 5x
8x+4x+5x= 187
17x= 187
x= 11
8x=8*11=88{number of re 1 coins}
4x=4*11=44{number of 50 Paisa coins}
5x=5*11=55{number of 10 Paisa coins}
Answered by
0
Answer:
there are 170 coins of 10 paise
Similar questions