A bag contains 187 Rs in the form of 1 Rupees 50 paisa & 10 paisa coins in 8:4:5 find no.of coins of each type
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HEY Buddy....!! here is ur answer
Answer : 1 rupees = 17.80 × 8 = 142.4
50 paise = 17.80×4 = 71.2
10 paise = 17.80×10 = 178
Solution :
Given that : A bag contains Rs. 187 in the form of 1 rupees, 50 paise and 10 paise in the ratio of 8:4:5
Let, the number of 1 rupees, 50 paise and 10 paise are 8x,4x and 5x respectively.
1 rupees
50 paise = 0.50 Rs.
10 paise = 0.10 paise.
According to the question :
1(8x) + 0.50(4x) + 0.10(5x) = 187
=> 8x+2x+0.5x = 187
=> 10.5x = 187
=> x = 17.80
Now, 1 rupees = 17.80 × 8 = 142.4
50 paise = 17.80×4 = 71.2
10 paise = 17.80×10 = 178
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
Answer : 1 rupees = 17.80 × 8 = 142.4
50 paise = 17.80×4 = 71.2
10 paise = 17.80×10 = 178
Solution :
Given that : A bag contains Rs. 187 in the form of 1 rupees, 50 paise and 10 paise in the ratio of 8:4:5
Let, the number of 1 rupees, 50 paise and 10 paise are 8x,4x and 5x respectively.
1 rupees
50 paise = 0.50 Rs.
10 paise = 0.10 paise.
According to the question :
1(8x) + 0.50(4x) + 0.10(5x) = 187
=> 8x+2x+0.5x = 187
=> 10.5x = 187
=> x = 17.80
Now, 1 rupees = 17.80 × 8 = 142.4
50 paise = 17.80×4 = 71.2
10 paise = 17.80×10 = 178
I hope it will be helpful for you...!!
THANK YOU ✌️✌️
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