A bag contains 1rupee ,50paise and 25paise coins in the ratio 5:7:8 respectively. If the total amount in the bag rupees 420, find the no of coins of each type
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Answer:
Let the ratio be rs. x. Then,
So,
Number of 1 rupee coins =5x
Number of 50 paise coins = 7x
Number of 25 paise coins = 8x
Now,
Value of 1 rupee coins =1×5x
= 5x
Value of 50 paise coins =50×7x
= 350x
Value of 25 paise coins = 25×8x
= 200x
Total value of all coins = (5x + 350x/100 + 200x/100)
But, It is given that the total amount is Rs.420
ACCORDING TO QUESTION
5x+3.5x+2x = Rs.420
10.5x = Rs.420
x = 420×10/105
x= Rs.40
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