Question

a bag contains 2 red, 3 green and 2 blue balls. two ball are drawn at random. what is the probability that 1)none of the ball draw is blue, 2)it is neither red nor green​

Answer 1

Answer:

1) 5/7

2) 2/7

Step-by-step explanation:

1) Total outcomes = 7 { 2 red balls + 3 green balls + 2 blue balls }

Favourable outcomes of getting none of the ball drawn is blue = 5 { 2 red balls + 3 green balls }

P(x) = Favourable outcomes / Total outcomes

P(getting none of the ball drawn is blue) = 5/7

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2) Total outcomes = 7 { 2 red balls + 3 green balls + 2 blue balls }

Favourable outcomes of getting ball neither red not green = 2 { 2 blue balls }

P(x) = Favourable outcomes / Total outcomes

P(getting ball neither red nor green) = 2/7

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• Probability deals with the occurence of the random event.

Answer 2

$\huge\bold\green{Question}$

A bag contains 2 red, 3 green and 2 blue balls. two ball are drawn at random. what is the probability that

(1 ) none of the ball draw is blue

(2) it is neither red nor green

$\huge\bold\green{Answer}$

( Part - 1 ) none of the ball draw is blue

→Total No . outcomes = 7

•Red balls = 2

•Green balls = 3

•Blue balls = 2

Favourable outcomes of getting none of the ball drawn is blue = 5 [ 3 green balls + 2 red balls ]

$\bold \green{p(x) = \frac{Favourable \: Outcomes}{Total \: Outcomes} }$

Hence the probability of non blue is →

P(getting none of the ball drawn is blue) = 5/7

(Part -2) it is neither red nor green

→ Total No. outcomes = 7

• Red balls = 2

• Green balls = 3

• Blue balls = 2

Favourable outcomes of getting ball neither red not green = 2 [ 2 blue balls ]

$\bold \green{p(x) = \frac{Favourable \: Outcomes}{Total \: Outcomes} }$

Hence the probability of neither Red nor green is →

P(getting ball neither red nor green) = 2/7