Question

A bag contains 2 red, 3 green and 2 blue gum balls. What is the probability of selecting a green one?

Answer 1

Answer:

3/7

Step-by-step explanation:

The probability of selecting green balls= Number of green balls / total number of balls

P=3/(2+3+2)

=3/7

Therefore the required probability is 3/7.

Answer 2

The probability of selecting a green gum ball = 3/7

Given :

A bag contains 2 red, 3 green and 2 blue gum balls

To find :

The probability of selecting a green gum ball

Solution :

Step 1 of 3 :

Find total number of possible outcomes

The bag contains 2 red, 3 green and 2 blue gum balls

Total number of gum balls

= 2 + 3 + 2

= 7

So total number of possible outcomes = 7

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that of selecting a green gum ball

There are 3 green gum balls in the bag

So total number of possible outcomes for the event A is 3

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{3}{7} }$

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