Question

a bag contains 2 red balls 3 black balls and 4 blue balls what is the probability of drawing (a) a red ball.
(b) a black ball (c) a blue ball​

Answer 1

Step-by-step explanation:

Total possible outcomes = 9 (2+3+4)

No. of red balls = 2

No. of black balls = 3

No of blue balls = 4

Probability of getting : -

:- a red ball -

2/9

:- a black ball -

3/9 = 1/3

:- a blue ball -

4/9

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Answer 2

Given :-

• A bag contains 2 red balls 3 black balls and 4 blue balls.

Have to Find :-

• What is the probability of drawing
• (a) a red ball. (b) a black ball (c) a blue ball.

Solution :-

Let's find out total number of outcomes → 2 + 3 + 4 ⇒ 9

Now,

1) Probability of drawing a red ball

No. Of favourable outcomes / Total number of outcomes

Fav outcomes → 2

Total no . → 9

P(E) of red ball ↬ 2/9

2) Probability of drawing a black ball

No. Of favourable outcomes / Total number of outcomes

Fav outcomes → 3

Total no . → 9

P(E) of black ball ↬ 3/9 → 1/3

3) Probability of drawing a blue ball$.$

No. Of favourable outcomes / Total number of outcomes

Fav outcomes → 4

Total no . → 9

P(E) of blue ball ↬ 4/9