Question

a bag
contains 2 red balls, 3 yellow balls and 4
green balls
balls A balli's drawn at random
from the bag. Find the probability that the
ball drawn
a.
green
b.
blu​

Answer 1

Answer:

red balls = 2

yellow balls = 3

green balls= 4

total no. of balls = 9 balls

A. probability of drawing green ball = 4/9

B. probability of drawing blue ball = 0/9 = 0 ( as there as no blue balls)

C. probability of yellow balls = 3/9 = 1/3

D. probability of red balls = 2/9

thanks;)

Answer 2

Step-by-step explanation:

No. of red balls = 2

No. of yellow balls = 3

No. of green balls = 4

Total no. of outcomes = 2+3+4 = 9

a.) Probability (Green ball) = Favourable outcomes ÷ Total no. of outcomes. = 4 ÷ 9

b.) Probability (Blue ball) = Favourable outcomes ÷ Total no. of outcomes. = 0 ÷ 9 = 0 ( As there is no blue balls )

(thanks;)