A bag contains 2 red balls, 4 green balls and 4 blue balls. If one ball is drawn at random, what is the probability that it is not blue?
Answers
Answered by
6
6/10=3/5
hopefully it is correct
hopefully it is correct
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Answered by
8
Hi there!
Number of red balls = 2
Number of green balls = 4
Number of blue balls = 4
Total number of balls = 10
If it is not a blue balls, then it has to be either red, or green.
So,
=> 2 + 4 / 10
=> 6/10
=> 3/5
The probability of not getting a blue ball is 3/5.
Hope it helps you!!
Number of red balls = 2
Number of green balls = 4
Number of blue balls = 4
Total number of balls = 10
If it is not a blue balls, then it has to be either red, or green.
So,
=> 2 + 4 / 10
=> 6/10
=> 3/5
The probability of not getting a blue ball is 3/5.
Hope it helps you!!
hai
nice answer
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