Question

A bag contains 2 red balls 4 green balls and 4 blue balls.if one ball is drawn at random, what is the probablity that is not blue

Answer 1

Total number of balls = 2 + 4 + 4 = 10 

Required number of balls = 2 + 4 = 6 



Probability = 6/10 = 3/5 

Answer 2

Probability =

$\frac{number \: of \: favourable \: outcomes}{number \: of \: possible \: outcomes}$
Here we have to find the probability of NOT A BLUE.
When we have to find NOT, then we subtract 1 from the given formula (see above)

So probability of blue = 4/10
since there are total 10 balls and only 4 blue balls.

Now the question is to find NOT A BLUE BALL.


So we'll subtract 1 from the probability. So,

$1 - \frac{4}{10} \\ = \frac{10}{10} - \frac{4}{10} = \frac{6}{10}$
6/10 is your answer.


Simplifying it 6/10 = 3/5


So 3/5 is your answer


$\frac{3}{5}$
Hope it helps dear friend ☺️✌️✌️