A bag contains 2 red marbles 3 green marbles and 4 blue marbles if we choose a marble then another without putting the 1st one back what is a probability that the 1st marble will be green and the 2nd will be red
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Answer:
1: 3/9 (for 1st marble which will be green)
2: 2/8=1/4 (for 2nd marble which will be red)
Step-by-step explanation:
Since you take away a marble after the first turn the total number of possible outcomes will be 8
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