Question

A bag contains 2 red marbles, 4 blue marbles and 7 green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be blue? Answer should be a fraction

Answer 1

Answer:

2/13 is the answer bro .Mark brainliest

Answer 2

Answer: 1/13

Step-by-step explanation:

First Marble :-

No. of Red Marbles = 2

No. of Blue Marbles = 4

No. of Green Marbles = 7

Total No. of Marbles = 13 = N(S)

No. of favourable outcomes = 4

Probability of Event = $\frac{No. of favourable outcomes}{Total no. of outcomes}$

therefore,

$P(E)=\frac{N(E)}{N(S)}$

P(E) = 4/13

Second Marble :-

No. Favourable outcomes = N(E)' = N(E)-1 = 3

Total No. Of outcomes = N(S)' = N(S)-1 = 12

P(E)' = 3/12

Final Probability of drawing both marbles are Red :-

$P(E)_{f} = P(E)*P(E)'$

= 4/13 x 3/12 = 1/13