Question

A bag contains 2 white, 3 black and 5 red balls. A ball is drawn from the bag. What is the probability of getting not a white ball? *​

Answer 1

heya mate!!! here is your answer...

the probability is 2/10

or you can also say 1/5

have a great day bro...

Answer 2

Step-by-step explanation:

Solution : Let `E_1`= envent of choosing bag A, <br> `E_2`= event of choosing bag B, and <br> E= event of drawing a red ball. <br> Then, `P(E-1)=1/2 and P(E-2)=1/2` <br> Also, `P(E//E_1)`= event of drawing a red ball from bag `A=3/5`, and <br> `P(E//E-2)` = event of drawing a red ball from bag `B=5/9`. <br> Probability of drawing a ball from B, it being given that it is red `=P(E_2//E)` <br> `=(P(E//E_2).P(E_2))/(P(E//E_1).P(E_1)+P(E//E_2).P(E_2))`[by Bayes's theorem] <br> `=((5/9xx1/2))/((3/5xx1/2)+(5/9xx1/2))=25/52`. <br> Hence, the required probability is `25/52`.