Question

A bag contains 2 white and 4 black balls and another bag contains 3 and 2 black balls. A ball is drawn at random.
answer is 8/15
show me solution


100 points for weight answer​

Answer 1

$answer$

Let E1 be the event that the ball is drawn from bag “X” and E2 be the event that the ball is drawn from bag“Y”.

Let E be the event that the ball drawn is white.

As both the bags are equally likely to be selected, we have p(E1) = ½ and P(E2) = ½

Hence, P(E/E1) = 2/5, P(E/E2) = 4/6 = 2/3

Therefore, P(E) = P(E1).P(E/E1) +P(E2).P(E/E2)

P(E) = (½). (⅖) + (½)(⅔)

P(E) = (2/10) + (2/6)

P(E) = 8/15