A bag contains 2 white and 4 black balls. Another bag contains 5 white
and 7 black balls. A ball is transformed from first bag to second bag. Then
a ball is drawn from second bag. Find the probability that it will be white.
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A= Event that white ball transferred
B= Event that black ball transferred
C= Event that ball drawn from secondary bag is white
⇒P ( ball drawn is white ) =P ( white ball transferred ) P ( Ball drawn white ) +P ( black ball transferred ) ×P ( ball drawn white )
=
9
4
×
14
7
+
9
5
×
14
6
=
126
28+30
=
126
58
Hence, the answer is
126
58
.
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